Optimal. Leaf size=568 \[ \frac{2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \text{Hypergeometric2F1}\left (\frac{1}{2} \left (\frac{3 b}{d}-n\right ),-n,\frac{1}{2} \left (\frac{3 b}{d}-n+2\right ),-e^{2 i (c+d x)}\right ) \exp (i (3 a-c n)+i x (3 b-d n)+i n (c+d x))}{3 b-d n}-\frac{3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \text{Hypergeometric2F1}\left (-n,\frac{b-d n}{2 d},\frac{1}{2} \left (\frac{b}{d}-n+2\right ),-e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac{3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \text{Hypergeometric2F1}\left (-n,-\frac{b+d n}{2 d},1-\frac{b+d n}{2 d},-e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n}+\frac{2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \text{Hypergeometric2F1}\left (-n,-\frac{3 b+d n}{2 d},\frac{1}{2} \left (-\frac{3 b}{d}-n+2\right ),-e^{2 i (c+d x)}\right ) \exp (-i (3 a+c n)-i x (3 b+d n)+i n (c+d x))}{3 b+d n} \]
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Rubi [A] time = 1.18036, antiderivative size = 568, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 4, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.235, Rules used = {4555, 2285, 2253, 2251} \[ \frac{2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (\frac{1}{2} \left (\frac{3 b}{d}-n\right ),-n;\frac{1}{2} \left (\frac{3 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (i (3 a-c n)+i x (3 b-d n)+i n (c+d x))}{3 b-d n}-\frac{3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,\frac{b-d n}{2 d};\frac{1}{2} \left (\frac{b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac{3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac{b+d n}{2 d};1-\frac{b+d n}{2 d};-e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n}+\frac{2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac{3 b+d n}{2 d};\frac{1}{2} \left (-\frac{3 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (-i (3 a+c n)-i x (3 b+d n)+i n (c+d x))}{3 b+d n} \]
Antiderivative was successfully verified.
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Rule 4555
Rule 2285
Rule 2253
Rule 2251
Rubi steps
\begin{align*} \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx &=2^{-3-n} \int \left (3 i e^{-i a-i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-3 i e^{i a+i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-i e^{-3 i a-3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n+i e^{3 i a+3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \, dx\\ &=-\left (\left (i 2^{-3-n}\right ) \int e^{-3 i a-3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx\right )+\left (i 2^{-3-n}\right ) \int e^{3 i a+3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx+\left (3 i 2^{-3-n}\right ) \int e^{-i a-i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx-\left (3 i 2^{-3-n}\right ) \int e^{i a+i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx\\ &=-\left (\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-3 i a-3 i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\right )+\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{3 i a+3 i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx+\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i a-i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i a+i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\\ &=\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i (3 a-c n)+i (3 b-d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i (3 a+c n)-i (3 b+d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i (a-c n)+i (b-d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx+\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i (a+c n)-i (b+d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\\ &=\frac{2^{-3-n} \exp (i (3 a-c n)+i (3 b-d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (\frac{1}{2} \left (\frac{3 b}{d}-n\right ),-n;\frac{1}{2} \left (2+\frac{3 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{3 b-d n}-\frac{3\ 2^{-3-n} \exp (i (a-c n)+i (b-d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (-n,\frac{b-d n}{2 d};\frac{1}{2} \left (2+\frac{b}{d}-n\right );-e^{2 i (c+d x)}\right )}{b-d n}-\frac{3\ 2^{-3-n} \exp (-i (a+c n)-i (b+d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (-n,-\frac{b+d n}{2 d};1-\frac{b+d n}{2 d};-e^{2 i (c+d x)}\right )}{b+d n}+\frac{2^{-3-n} \exp (-i (3 a+c n)-i (3 b+d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (-n,-\frac{3 b+d n}{2 d};\frac{1}{2} \left (2-\frac{3 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{3 b+d n}\\ \end{align*}
Mathematica [A] time = 24.6439, size = 329, normalized size = 0.58 \[ 2^{-n-3} \left (e^{-i (c+d x)} \left (1+e^{2 i (c+d x)}\right )\right )^{n+1} e^{i (-3 a+c+d (n+1) x)} \left (-\frac{3 e^{2 i a-i x (b+d n)} \text{Hypergeometric2F1}\left (1,\frac{1}{2} \left (-\frac{b}{d}+n+2\right ),-\frac{b+d (n-2)}{2 d},-e^{2 i (c+d x)}\right )}{b+d n}+e^{i (4 a+b x-d n x)} \left (\frac{e^{2 i (a+b x)} \text{Hypergeometric2F1}\left (1,\frac{1}{2} \left (\frac{3 b}{d}+n+2\right ),\frac{3 b}{2 d}-\frac{n}{2}+1,-e^{2 i (c+d x)}\right )}{3 b-d n}-\frac{3 \text{Hypergeometric2F1}\left (1,\frac{b+d (n+2)}{2 d},\frac{1}{2} \left (\frac{b}{d}-n+2\right ),-e^{2 i (c+d x)}\right )}{b-d n}\right )+\frac{e^{-i x (3 b+d n)} \text{Hypergeometric2F1}\left (1,\frac{1}{2} \left (-\frac{3 b}{d}+n+2\right ),-\frac{3 b}{2 d}-\frac{n}{2}+1,-e^{2 i (c+d x)}\right )}{3 b+d n}\right ) \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.762, size = 0, normalized size = 0. \begin{align*} \int \left ( \cos \left ( dx+c \right ) \right ) ^{n} \left ( \sin \left ( bx+a \right ) \right ) ^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \cos \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-{\left (\cos \left (b x + a\right )^{2} - 1\right )} \cos \left (d x + c\right )^{n} \sin \left (b x + a\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \cos \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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